Question

calcule o 3° termo no desenvolvimento de (2+3x)6

Answer 1

(2+3x)^6
p+1=3 ==> p=2
T[p+1]=C(n,p).a^(n-p).b^p
T[2+1]=C(6,2).2^(6-2).(3x)²
T[3]=6!/2!(6-2)!.2^4.9x²
T[3]=6!/2!4!.16.9x²
T[3]=6.5.4!/2!4!.16.9x²
T[3]=15.16.9x²
T[3]=2.160x² #