Question

F(X)=X²+2X-3
alguém sabe?​

Answer 1

Resposta:

As raízes da equação são -3 e 1.

Explicação passo-a-passo:

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Usando Bhaskara

$f(x)=x^2+2x-3\\\\\\a=1\\b=2\\c=-3\\\\\Delta=b^2-4\;.\;a\;.\;c=2^2-4\;.\;1\;.\;-3=4+12=16\\\\\\x=\dfrac{-b \pm \sqrt{\Delta}}{2\;.\;a}=\dfrac{-2 \pm \sqrt{16}}{2\;.\;1}=\dfrac{-2 \pm 4}{2}\\\\\\x_1=\dfrac{-2+4}{2}=\dfrac{2}{2}=1\\\\x_2=\dfrac{-2-4}{2}=\dfrac{-6}{2}=-3\\\\\\\boxed{S=\{-3,1\}}$