Question

ME AJUDEM, PARA HOJEEE. Por favor!!
Função logarítima

Answer 1

log[k] c

= log c/log k

= [log k/log c]^(-1)

=[log[c] k]^(-1)

=[1/3]^(-1)

=3

log[b] k =

=log k/ log b

=[log b/ log k]^(-1)

=[-1]^(-1)

=-1

a)

log[c] k =1/3

log k/log c =1/3

[log k/log c]^(-1)= [1/3]^(-1)

log c /log k =3

log[k] c =3

b)

log[k] a + log [k] b=4-1=3

c)

loh[k] b+ log[k] k - log[k] c

=-1+1-(3)=-3

d)

log[b] b + log[b] k

= 1 -1=0

e)

(2/3)* log[k] a

=(2/3) *4=8/3

f)

log[a] k =log k /log a

=[log a/ log k]^(-1)

=[4]^(-1)=1/4