Question

Resolva a equação (4^x)-5.(2^x)+6=0

Answer 1

Oi Tiago

4^x - 5*2^x + 6 = 0

(2^x)² - 5*2^x + 6 = 0

y = 2^x

y² - 5y + 6 = 0

delta
d² = 25 - 24 = 1
d = 1

y1 = (5 + 1)/2 = 3
y2 = (5 - 1)/2 = 2

2^x = 3
xlog(2) = log(3)

x = log(3)/log(2)

2^x = 2
x = 1