Question

RESOLVA A INEQUAÇAO 2 < log2 ( 3x + 1) < 4

Answer 1

Resposta:

1 < x < 5

Explicação passo-a-passo:

log$_{2}$(3x + 1) > 2

$2^2$ < 3x + 1

3x > 3

x > 1

log$_{2}$(3x + 1) < 4

$4^2$ > 3x + 1

3x < 15

x < 5

Logo, 1 < x < 5