Question

Determine as coordenadas do vértice da função f(x)=x²-3x+9

Answer 1

x²-3x+9=0

Delta=b²-4ac

Delta=(-3)²-4.1.9

Delta=9-36

Delta=-27

Xv=-b/2a   Xv=3/2

Yv=-Delta/4a    Yv=27/4

V(3/2;27/4)

Answer 2

f(x) = x² - 3x + 9

x² - 3x + 9 = 0

a = 1
b = - 3
c = 9

Δ = b² - 4ac
Δ = (-3)² - 4(1)(9)
Δ = 9 - 36
Δ = - 27

Coordenada do vértice (x, y)

xV = - b / 2a

xV = - (- 3) / 2
xV = 3/2

yV = - Δ / 4a
yV = - (-27) / 4
yV = 27/4

S = (3/2 , 27/4)