Question

Y=[(1+logp m).log pm c]-log pc

Answer 1

y = [(1 + log[p] M) . log[pm] C] - log[p] C 

y = [(1 + log[p] M) .( log[p]C/log[p] PM)] - log[p] C 

y = [(1 + log[p] M) .( log[p]C/log[p] P + log[p]M)] - log[p] C 

y = [(1 + log[p] M) .( log[p]C/1 + log[p]M)] - log[p] C 

y = [(1 + log[p] M) .( log[p]C)/(1 + log[p]M)] - log[p] C 

y = log[p] C - log[p] C 

y = 0