Question

2x/5y+3x/4y fracionada

Answer 1

Determina-se o denominador comum das frações. Sendo ele igual a 20xy²

$[tex] \frac{2x}{5y}+ \frac{3x}{4y} = \frac{8xy}{20y^{2} } +\frac{15xy}{20y^{2} } =\frac{8xy+15xy}{20y^{2} } =\frac{23xy}{20y^{2} } = \frac{23x}{20y}$ [/tex]

Answer 2

$\dfrac{2x}{5y} + \dfrac{3x}{4y}$


MMC = 20y²


$\dfrac{4y *2x +5y * 3x }{20y^2} \\ \\ \\ \dfrac{8xy +15xy }{20y^2} \\ \\ \\ \dfrac{23xy }{20y^2} \\ \\ \\ =\ \textgreater \ \dfrac{23x }{20y}$