Question

y=x²-7x+13

determine as coordenadas do vértice da parábola que representa o gráfico

me ajudem

Answer 1

$y= x^{2} -7x+13\\\\x^{2} -7x+13=0\\\\\\a=1\\b=-7\\c=13 \\\\x_v= \dfrac{-b}{2a} \to~~ x_v= \dfrac{-(-7)}{2.1} \to~~ \boxed{ x_v= \dfrac{7}{2}}\\\\\\ y_v= \dfrac{-\Delta}{4a} \to\\\\ \Delta=b^2-4ac\to~ \Delta=(-7)^2-4.1.13\to~ \Delta=49-52\to\boxed{\Delta=-3 } \\\\ y_v= \dfrac{-(-3) }{4.1} \to~~ \boxed{ y_v= \dfrac{3}{4}} \\\\\\\\\\ \large\boxed{\boxed{V=\left\{ \dfrac{7}{2} ~;~ \dfrac{3}{4} \right\}}}$