Question

Ache as raízes da equação 2x^2-7x+6=0

Answer 1

Resposta:

2x^2-7x+6=0

x'=[7+√((-7)²-4*2*6)]/(2*2)=(7+√(49-48)]/4=(7+1)/4=2

x''=[7-√((-7)²-4*2*6)]/(2*2)=(7-√(49-48)]/4=(7-1)/4=6/4=3/2