Question

Sabendo que log 2 = 0,301 , log 3 = 0,477 e log 5 = 0,699, calcule (15/24) log​

Answer 1

$\mathrm{Dados:}\ \log{2}\approx0.301;\ \log{3}\approx0.477;\ \log{5}\approx0.699.$

$\log{\bigg(\dfrac{15}{24}\bigg)}=\log{\bigg(\dfrac{3\times5}{3\times8}\bigg)}=\log{\bigg(\dfrac{5}{2^3}\bigg)}=\log{5}-3\log{2}$

$\Longrightarrow\log{\bigg(\dfrac{15}{24}\bigg)}\approx 0.699-3(0.301)\ \therefore\ \boxed{\log{\bigg(\dfrac{15}{24}\bigg)}\approx-0.204}$