Question

Encontre as raizes das funções
F(x) =x2-20x+36

Answer 1

Explicação passo-a-passo:

Temos a seguinte função:

$\boxed{f(x)=x^{2} -20x+36}$

Calculando as raízes da função:

$f(x)=0\\\\x^{2} -20x+36=0 \implies a=1\ ,\ b=-20\ e\ c=36\\\\\Delta=b^{2}-4ac\\\\\Delta=(-20)^{2}-4.1.36\\\\\Delta=400-144\\\\\Delta=256\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-(-20)\pm\sqrt{256}}{2.1}\\\\x_{1} =\dfrac{20+16}{2}=\dfrac{36}{2} \\\\\boxed{\boxed{x_{1} =18} } \\\\x_{2} =\dfrac{20-16}{2}=\dfrac{4}{2} \\\\\boxed{\boxed{x_{2} =2} }$

Answer 2

x² - 20x + 36 =

A = 1

B = -20

C = 36

∆ = b² - 4 × a × c

∆ = -20² - 4 × 1 × 36

∆ = - 400 - 144

∆ = - √544

∆ = -23,3

Espero ter ajudado.

Tchau tchau!!! :-)