Question

3 – Aplicando a fatoração em X2 + X – 6, encontramos:

(A) (x – 1).(x + 6)
(B) (x – 2).(x + 3)
(C) (x – 6).(x – 1)
(D) (x – 1).(x + 1)
(E) (x – 2).(x – 3)

Answer 1

Resposta: letra B.

Explicação passo-a-passo:

X^2+x-6

A=1 B=1 C=-6

X= -b+-\/´´b^2-4.a.c´

´´´´´´´´´´´´´´´´2´´´´´´´´´´´´´´´´´´

X= -1 +-\/´´´1-4.1.(-6)

´´´´´´´´´´´´´´2.1`````````````````

X= -1 +-\/´´´1+ 24´´´´´

´´´´´´´´´´´´´´´2´´´´´´´´´´´´´´

X= -1 +-\/´´´25

´´´´´´´´´´´´´2´´´´´´´´´´´

X= -1 +-5

´´´´´´´´2´´´´´´´´´´

X1= -1+5= 4 ÷2 = 2

´´´´´´´´´2´´´´´

X2= -1 -5 = 6÷2 = 3

´´´´´´´´´2´´´´´´

( x -2) . (x +3)

Answer 2

Resposta:

Letra B

Explicação passo-a-passo:

S = 1 e P = -6

x² + Sx + p = 0

x² + 1x - 6 = (x - 2)(x + 3)