Question

pfv me ajudem eu imploro​​

Answer 1

A- 49

B- (-4)

C-0,316406

D-1

E- -1

27

F- 0,36

Answer 2

Resposta:

a) (+7)²= (+7). (+7)= 49

b)

$(-4)^1= -4$

c)

$\left[\begin{array}{ccc}\frac{3}{4} \end{array}\right] ^4=\left[\begin{array}{ccc}\frac{81}{256} \end{array}\right]= \frac{81}{256}$

d) $5^0=1$

e)

$(-3)^{-3} =\left[\begin{array}{ccc}-\frac{1}{3} \end{array}\right] ^3=-\frac{1}{27}$

f)

$(-0,6)^{-2} = \left[\begin{array}{ccc}-\frac{1}{0,6} \end{array}\right] ^{2}= -\frac{1}{0,36} =\frac{1}{\frac{36}{10} } \\\frac{1}{1}. \frac{10}{36} =\frac{10}{36}$⇒simplificando os dois termos por 2 temos

$\frac{10:2}{36:2} =\frac{5}{18}$