Question

Calcule a altura necessaria para que
um corpo de 4,5 kg apresente uma
energia potencial gravitacional de
1350J. Considere a gravidade local
igual a 10 m/s? *
50 m
30 m
20 m
15 m

Answer 1

$\Large\displaystyle\text{ \begin{gathered} \hookrightarrow \boxed{ \boxed{ \bf h = 30 \:m}} \end{gathered} }$

• Explicação:

$\Large\displaystyle\text{ \begin{gathered} \sf{ E_{Pg} = m \cdot g \cdot{h} } \end{gathered} }$

$\Large\displaystyle\begin{gathered} \sf{ 1350 = 4,5\cdot10h } \end{gathered}$

$\Large\displaystyle\begin{gathered} \sf{ 1350 = 45h } \end{gathered}$

$\Large\displaystyle\begin{gathered} \sf{ 45h = 1350 } \end{gathered}$

$\Large\displaystyle\text{ \begin{gathered} \sf{ h = \dfrac{1350}{45} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \boxed{ \boxed{ \sf{ h = 30 \: m }}} \end{gathered} }$