Question

sendo log 2 = 0,301 e log 3= 0,477 calcule log 7,2

Answer 1

$\boxed{log (7,2) \to log( \frac{72}{10}) \to log(72) -log(10) }$

$log(72) -log(10) \to log(2^3*3^2) - 1\to log(2)^3+log(3^2) - 1$

$log(2)^3+log(3^2) - 1 \to 3*log(2) + 2*log(3) - 1 \to$

$3*log(2) + 2*log(3) - 1 \to 3*(0,301)+2*(0,477) - 1 =$

$\boxed{\boxed{0,903+0,954 - 1 = 1,857-1 = 0,857}}$

Espero ter ajudado. :))