• Matéria: Matemática
  • Autor: diva14
  • Perguntado 9 anos atrás

Sendo u=(2,3,1) e v=(1,4,5), calcule:
a) (u+v)²
b) (3u-2v)²

Respostas

respondido por: aldhemah
23
a) (u+v)^2=(2+1, 3+4, 1+5)^2=(3, 7, 6)^2=(9, 49, 36)

b) [3(2,3,1) -2(1,4,5)]^2
[(6,9,3) - (2,8,10)]^2
(6-2, 9-8, 3-10)^2
(4,1,-7)^2= (16, 1, 49)
respondido por: BrivaldoSilva
5
a)   (2 + 1 ,  3 + 4 ,   1 + 5) ^2 = ( 3 , 7, 6) ^2 = ( 9, 49, 36)

[(3(2,3,1) - 2(1,4,5)] ^2 
[(6,9,3) -  (2,8,10)]^2
[ 4, 1 , -7]^2 = [16, 1, 49]





 
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