• Matéria: Matemática
  • Autor: leticiamelloo7
  • Perguntado 9 anos atrás

Sendo log2=0.30, log3=0.48, log5=0.70, calcule: 

a)log30

b)log180

Respostas

respondido por: Luanferrao
1
log\ 30 = log\ 2.3.5 = log\ 2+log\ 3+log\ 5\\\\\ 0,30+0,48+0,7 =1,48 \\\\ \boxed{log\ 30 = 1,48}

log\ 180 = log\ 2^2.3^2.5 = 2\ log\ 2+2\ log\ 3+log\ 5\\\\\ 2(0,30)+2(0,48)+0,70 = \\\\\ 0,60+0,96+0,70 = 2,26\\\\ \boxed{log\ 180 = 2,26}
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