Question

Alguém................​

Answer 1

Resposta:

A)

(3x-2)/3= [(3x-2)+(x+1)]/(3+2)

(3x-2)/3= [4x-1]/5

15x-10=12x-3

3x=7

x=7/3

B)

(x-5)/3= (x-5+x+1)/7

(x-5)/3= (2x-4)/7

7x-35=6x-12

x=35-12

x=23

C)

(4x-12)/(2x+2)=24/16

16*(4x-12)=24*(2x+2)

64x-192=48x+48

16x=192+48

16x=240

x=15

Answer 2

Resposta:

A) (3x-2)/3= [(3x-2)+(x+1)]/(3+2) (3x-2)/3= [4x-1]/5 15x-10-12x-3 3x=7 x=7/3

B) (x-5)/3= (x-5+x+1)/7 (x-5)/3= (2x-4)/7

C) (4x-12)/(2x+2)=24/16 16*(4x-12)=24*(2x+2) 64x-192-48x+48 16x=192+48 16x=240 x=15