Question

Calcule as diferenças dos quadrados determinando a expressão e o valor numérico sendo valor de p=3 e q=-1
a) ( q + 1).(q – 1)=
b) (p- 3).( p+3)=

Answer 1

Resposta:

a)

$(q+1)(q-1)=0\\\\q^{2}-q+q-1=0\\\\q^{2}-1=0\\\\(-1)^{2}-1=0\\\\1-1=0\\\\0=0$

b)

$(p-3)(p+3)=0\\\\p^{2}+3p-3p-9=0\\\\p^{2}-9=0\\\\(3)^2-9=0\\\\9-9=0\\\\0=0$