Question

a) 4⁻²+ 10⁻² =
b) 4⁻³ . 10⁻² =
c) 4⁻² : 10⁻¹=

Answer 1

$a) 4 ^{-2}+10^{-2} = \frac{1}{4 ^{2} } + \frac{1}{10 ^{2} } = \frac{1}{16} + \frac{1}{100} = \frac{25+4}{400} = \frac{29}{400}$
$b)4^{-3} * 10^{-2} = \frac{1}{ 4^{3} }* \frac{1}{ 10^{2} } = \frac{1}{64*100} = \frac{1}{6400}$
$c) \frac{4^{-2}}{10^{-1}} = \frac{ \frac{1}{ 4^{2} } }{ \frac{1}{10} }= \frac{1}{16} * \frac{10}{1} = \frac{10}{16}= \frac{5}{8}$