Question

Dada a função f(X)= 3 x² -4 x + 1, determine: a)f(1), b) f(-2) , c) f( - 1/4) *

Answer 1

Resposta:

f(x)= 3x² - 4x + 1

a) f(1)

f(1)= 3.1² - 4.1 + 1

f(1) = 3.1 - 4 + 1

f(1) = 3 - 3

f(1) = 0

b) f(-2)

f(-2) = 3.(-2)² - 4(-2) + 1

f(-2) = 3.4 + 8 + 1

f(-2) = 12 + 9

f(-2) = 21

c) f($-\frac{1}{4}$)

f($-\frac{1}{4}$) = 3.($-\frac{1}{4}$)² - 4.($-\frac{1}{4}$) + 1

f($-\frac{1}{4}$) = 3.($\frac{1}{16}$) - 4.($-\frac{1}{4}$) + 1

f($-\frac{1}{4}$) = $\frac{3}{16}+1+1$

f($-\frac{1}{4}$) = $\frac{3}{16}+2$

f($-\frac{1}{4}$) = $\frac{35}{16}$

Bons estudos!

Answer 2

Olá

a) f(1)=3.1²-4.1+1

   f(1)=3-4+1

   f(1)=1

b) f(-2)=3.(-2)²-4.(-2)+1