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(x+1/5)x(x+1/5)
x²+x/5+x/5+1/25
x²+2x/5+1/25=0
Δ= (2/5)²-4x1x1/25
Δ=4/25-4/25
Δ=0
OBS: Δ=0--- x'=x"
x=(-2/5+-√0)/2
x'=x"= -2/5+0/2=
-2/5/2=
-2/10=
x= -1/5
x²+x/5+x/5+1/25
x²+2x/5+1/25=0
Δ= (2/5)²-4x1x1/25
Δ=4/25-4/25
Δ=0
OBS: Δ=0--- x'=x"
x=(-2/5+-√0)/2
x'=x"= -2/5+0/2=
-2/5/2=
-2/10=
x= -1/5
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