Question

conjunto solução da equação q⁴-13q²+36=0

Answer 1

Δ = b²-4ac
Δ = (-13)² - 4.1.36
Δ = 169 - 144
Δ = 25

$q^2= \frac{-(-13)-5}{2} =\ \textgreater \ q^2= \frac{8}{2}=\ \textgreater \ q^2=4=\ \textgreater \ q=-2,ou, q=2 \\ ou, q^2= \frac{-(-13)+5}{2} =\ \textgreater \ q^2= \frac{18}{2} =\ \textgreater \ q^2=9=\ \textgreater \ q=-3,ou,q=3 \\ S={-3,-2,2,3}$