Question

resolva a a seguinte equação exponencial: (1/1000)^2x + 1 = √10

Answer 1

Se a equação for: $( \frac{1}{1000})^{2X+1}= \sqrt{10}$

$( \frac{ 10^{0} }{ 10^{3} } )^{2X+1}= 10^{ \frac{1}{2} }$
$(10^{-3})^{2X+1} = 10^{ \frac{1}{2} }$
$10^{(-6x-3)} = 10^{ \frac{1}{2} }$
$-6X-3= \frac{1}{2}$
$-6X= \frac{1}{2} + \frac{6}{2}$
$-6X= \frac{7}{2}$
$X= \frac{-7}{12}$