Question

$(m - 3 {)}^{2}$

$(2a - 5 {)}^{2}$

$(7 - 3c {)}^{2}$

$(5x - 2y {)}^{2}$

$(4m - 1 {)}^{2}$

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Answer 1

Explicação passo-a-passo:

$(m - 3 {)}^{2}$ = (m-3).(m-3)

$(2a - 5 {)}^{2}$ = (2a -5).(2a -5)

$(7 - 3c {)}^{2}$ = (7 - 3c) (7 - 3c)

$(5x - 2y {)}^{2}$ = (5x -2y).(5x - 2y)

$(4m - 1 {)}^{2}$ = (4m - 1).(4m - 1)

Answer 2

Lembrando que:

$(a - b)^2 = a^2 -2ab + b^2$

Assim:

$(m-3)^2 = m^2 -6m + 9\\(2a-5)^2 = 4a^2 -20a+25\\(7-3c)^2 = 49 - 42c+9c^2\\(5x-2y)^2 = 25x^2 -20xy + 4y^2\\(4m-1)^2 = 16m^2 - 8m+1$