Question

alguém pode me ajudar nessas questões?

De preferência a 2 e 3, mas se souberem todas melhor.

Agradeço

Answer 1

.
$\frac{MN}{OP} = \frac{OP}{ST} \\ \\ \frac{40cm}{24cm} = \frac{35cm}{ST} \\ \\ simplifique~~ \frac{40}{24} \\ \\ \frac{5}{3} = \frac{35}{ST} \\ \\ ST= \frac{3.35}{3} \\ \\ ST=21cm$

3)
$\frac{20}{x} = \frac{24}{y} = \frac{32}{z} \\ \\ x+y+z=152$

$\frac{20+24+32}{x+y+z} = \frac{76}{152} = \frac{1}{2}$

$\frac{1}{2} = \frac{20}{x} \\ \\ x=2.20 \\ x=40 \\ \\ \frac{1}{2} = \frac{24}{y} \\ y=2.24 \\ y=48 \\ \\ \frac{1}{2} = \frac{32}{z} \\ z=2.32 \\ z=64$

4)
$\frac{2}{16} = \frac{x}{7x+3} \\ \\ \frac{1}{8} = \frac{x}{7x+3} \\ \\ 8x=7x+3 \\ 8x-7x=3 \\ x=3$

$MP=7x+3 \\ MP=7(3)+3 \\ MP=21+3 \\ MP=24$

5)
$\frac{x+6}{3x+4} = \frac{\not16^4}{\not20^5} \\ \\ 4(3x+4)=5(x+6) \\ 12x+16=5x+30 \\ 12x-5x=30-16 \\ 7x=14 \\ x=14\div7 \\ x=2$

perímetro

x+6+3x+4+30+20+16=
2+6+6+4+30+20+16=
18+50+16=
P=84