Question

Determinar as coordenadas dos pontos A, B e C conhecendo-se os pontos médios M(-2,1), N(5,2) e P(2,-3).

Answer 1

(xa+xb)/2=-2
(xb+xc)/2=5
(xc+xa)/2=2
(ya+yb)/2=1
(yb+yc)/2=2
(yc+ya)/2=-3

=xa+xb=-4
xb+xc=10
xc+xa=4
ya+yb=2
yb+yc=4
yc+ya=-6

. xa+xb=-4
(-) xc+xa=4

=xb-xc=-8

. xb-xc=-8
(+) xb+xc=10

=2xb=2
=xb=1

xa+xb=-4
xa+1=-4
xa=-5

xb+xc=10
1+xc=10
xc=9

. ya+yb=2
(-) yc+ya=-6

=yb-yc=8

. yb-yc=8
(+) yb+yc=4

=2yb=12
yb=6

ya+yb=2
ya+6=2
ya=-4

yb+yc=4
6+yc=4
yc=-2

xa=-5 , ya=-4
xb=1, yb=6
xc=9, yc=-2

logo:

A(-5,-4) B(1,6) e C(9,-2)