Question

De que modo resolvo a questão?

Answer 1

$\frac{20(4^n^+^1+4^n^-^1)}{17(4^n+4^n^+^1)} = \frac{20.4^n^-^1(4^2+1)}{17.4^n(1+4)}= \frac{20.17.4^n^-^1}{17.5.4^n} \\ \frac{4.4^n^-^1}{4^n} = \frac{4. \frac{4^n}{4} }{4^n} = \frac{4^n}{4^n} = 1$