• Matéria: Matemática
  • Autor: ingrydcristine61
  • Perguntado 4 anos atrás

Seja a função f(x) = 2x² - 4x + 12, determine:

a) f(2)

b) f(-4)

c) f(5)

d) f(-3)

e) f(0)

f) f(1/4)​

Respostas

respondido por: wendelbisneto
1

Resposta:

a) f(x)= 2x²-4x+12

f(2)= 2.2²-4.2+12= 8-8+12=12

b)f(-4)= 2.(-4)²- 4.(-4) +12= 2. 16 + 16+12= 32+16+12=60

c) f(5) = 2.5²- 4.5 +12= 2.25+ 20+12= 50+20+12= 82

d) f(-3)= 2.(-3)²-4.(-3)+12= 2.9+12+12= 42

e) f(0)= 2.0²-4.0+12= 0+0+12=12

f) f(1/4) = 2.(1/4) ²- 4.(1/4) +12= 2.(1/16)- (4/4) +12= 2/16-1+12= 2/16 +11= (2+ 16.11)/16=178/16

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