Question

Resolva a expressão abaixo:​

Answer 1

$[(10^{0}-2^{3}*4^{3} )*3^{2} ]^{1} /(2^{3} *3^{2} ) =$

$[(1-2^{3}*4^{3} )*3^{2} ]^{1} /(8*9) =$

$(1-2^{3}*4^{3} )*3^{2} /72 =$

$(1-(2*4)^{3} )*3^{2} /72 =$

$(1-8^{3} )*3^{2} /72 =$

$\frac{(1-8^{3} )*3^{2}}{72} =$

$\frac{(1-8^{3} )*9}{72} =$

$\frac{1-8^{3} }{8} =$

$\frac{1-512}{8} =$

$-\frac{511}{8}$