Question

resolva a equação (n-2)!/(n-1)!=1/5

Answer 1

$\frac{(n-2)!}{(n-1)!} = \frac{1}{5} \\ \\ \frac{(n-2)!}{(n-1).(n-2)!} = \frac{1}{5} \\ \\ \frac{1}{n-1} = \frac{1}{5} \\ \\ 5.1=n-1 \\ \\ n=5+1 \\ \\ n=6$

Answer 2

(n-2)!/(n-1)!= 1/5∴ (n-2)!/(n-1).(n-2)!/1/5, corta (n-2)!, temos, 1/(n-1)=1/5∴ n-1=5∴ n=5+1= 6