Question

ajudem , dou 10 pontos , preciso pra agr

Answer 1

sai por semelhança  saiba que o lado AD = x

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$\frac{AC}{DE} = \frac{AD}{DB} \\\\ \frac{6}{2} = \frac{x+3}{3} \\\\ 3*3 = x+3\\\\9 = x+3\\\\ x=9-3\\\\ x = 6\\\\\\ \\ logo~AB=x+3\\\\ AB=6+3\\\\ \boxed{AB=9m}$

Answer 2

Ola Thiago 

tg(B) = 6/(x + 3) = 2/3

18 = 2x + 6 

2x = 12 

x = 6

AB  = x + 3 = 6 + 3 = 9 m (D)