Question

qual valor de x e de y na figuraabaixo??​

Answer 1

Resposta:

$x=\frac{5\sqrt{3} }{2} \\\\y=\frac{5}{2}$

Explicação passo-a-passo:

Seja m a medida do cateto no triângulo maior.

m² + 12² = 13²

m² + 144 = 169

m² = 169- 144

m² = 25

m² = 5²

m = 5

$\frac{x}{m}= sen60\°\\\\\frac{x}{5}=\frac{\sqrt{3} }{2}\\\\2x=5\sqrt{3}\\\\x=\frac{5\sqrt{3} }{2}\\\\\frac{y}{m}=cos60\°\\\\\frac{y}{5}=\frac{1}{2}\\\\2y =5\\\\y=\frac{5}{2}$