Respostas
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Boa tarde Danilo!
Solução!
![(2-3i)-(3-i).2i \\\\\
(2-3i)-(6i-2i^{2})\\\\\
(2-3i)+(-6i+2i^{2})\\\\\
Lembrando~~que~~i^{2}=-1\\\\\
(2-3i)+(-6i+2(-1)) \\\\\
(2-3i)+(-6i-2)\\\\\
(2-2-3i-6i) \\\\\
(0-9i)=-9i](https://tex.z-dn.net/?f=%282-3i%29-%283-i%29.2i+%5C%5C%5C%5C%5C%0A%282-3i%29-%286i-2i%5E%7B2%7D%29%5C%5C%5C%5C%5C%0A%282-3i%29%2B%28-6i%2B2i%5E%7B2%7D%29%5C%5C%5C%5C%5C%0ALembrando%7E%7Eque%7E%7Ei%5E%7B2%7D%3D-1%5C%5C%5C%5C%5C%0A%282-3i%29%2B%28-6i%2B2%28-1%29%29+%5C%5C%5C%5C%5C%0A%282-3i%29%2B%28-6i-2%29%5C%5C%5C%5C%5C%0A%282-2-3i-6i%29+%5C%5C%5C%5C%5C%0A%280-9i%29%3D-9i++ "(2-3i)-(3-i).2i \\\\\
(2-3i)-(6i-2i^{2})\\\\\
(2-3i)+(-6i+2i^{2})\\\\\
Lembrando~~que~~i^{2}=-1\\\\\
(2-3i)+(-6i+2(-1)) \\\\\
(2-3i)+(-6i-2)\\\\\
(2-2-3i-6i) \\\\\
(0-9i)=-9i")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
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