Question

t² + 6 t + 8 = 0? ME AJUDEM

Answer 1

Δ = b² - 4*a*c

Δ = 6² - 4*1*8

Δ = 36 - 32

Δ = 4

T = -b ± √Δ
     -----------
          2*a

T = - 6 ± 6
      -----------
            2

T¹ = 12/2 = 6

T² = 0/2 = 0