Respostas
Resposta:
a) x' = 2
x" = - 5
b) x' = 1/3
x" = - 1/2
c) x' = 3/2
x" = 1/2
d) x' = x" = 3
e) x' = - 3
x" = 4
Explicação passo-a-passo:
a) x² + 3x - 10 = 0
a = 1, b = 3, c = - 10
Δ = b² - 4ac
Δ = (3)² - 4. 1. - 10
Δ = 9 + 40
Δ = 49
x = - b ± √Δ / 2a
x = - (3) ± √49 / 2.1
x = - 3 ± 7 / 2
x' = - 3 + 7 / 2 = 4 / 2 = 2
x" = - 3 - 7 / 2 = - 10 / 2 = - 5
b) 6x² + x - 1 = 0
a = 6, b = 1, c = - 1
Δ = b² - 4ac
Δ = (1)² - 4. 6. - 1
Δ = 1 + 24
Δ = 25
x = - b ± √Δ / 2a
x = - (1) ± √25 / 2.6
x = - 1 ± 5 / 12
x' = - 1 + 5 / 12 = 4/12 = 1/3
x" = - 1 - 5 / 12 = - 6/12 = - 1/2
c) 2x² - 4x + 3 = 0
a = 2, b = - 4, c = 3
Δ = b² - 4ac
Δ = (- 4)² - 4. 1. 3
Δ = 16 - 12
Δ = 4
x = - b ± √Δ / 2a
x = - (- 4) ± √4 / 2.2
x = 4 ± 2 / 4
x' = 4 + 2 / 4 = 6/4 = 3/2
x" = 4 - 2 / 4 = 2/4 = 1/2
d) x² - 6x + 9 = 0
a = 1, b = - 6, c = 9
Δ = b² - 4ac
Δ = (- 6)² - 4. 1. 9
Δ = 36 - 36
Δ = 0
x = - b ± √Δ / 2a
x = - (- 6) ± √0 / 2.1
x = 6 ± 0 / 2
x' = 6 + 0 / 2 = 6/2 = 3
x" = 6 - 0 / 2 = 6/2 = 3
e) - x² + x + 12 = 0
a = - 1, b = 1, c = 12
Δ = b² - 4ac
Δ = (1)² - 4. - 1. 12
Δ = 1 + 48
Δ = 49
x = - b ± √Δ / 2a
x = - (1) ± √49 / 2. - 1
x = - 1 ± 7 / - 2
x' = - 1 + 7 / - 2 = 6/ - 2 = - 3
x" = - 1 - 7 / - 2 = - 8/ - 2 = 4
Espero ter ajudado!!