• Matéria: Matemática
  • Autor: Anônimo
  • Perguntado 4 anos atrás

Encontre o valor do x e do y... alguém pode me ajudar?

Anexos:

Respostas

respondido por: CyberKirito
1

\boxed{\begin{array}{l}\tt d)~\sf cos(30^\circ)=\dfrac{36\sqrt{2}}{y}\\\sf\dfrac{\sqrt{3}}{2}=\dfrac{36\sqrt{2}}{y}\\\sf\sqrt{3}y=72\sqrt{2}\\\sf y=\dfrac{72\sqrt{2}}{\sqrt{3}}\\\sf y=\dfrac{72\sqrt{6}}{3}\\\sf y=24\sqrt{6}\\\sf tg(30^\circ)=\dfrac{x}{36\sqrt{2}}\\\sf\dfrac{\sqrt{3}}{3}=\dfrac{x}{36\sqrt{2}}\\\sf x=\dfrac{36\sqrt{2}\cdot\sqrt{3}}{3}\\\sf x=12\sqrt{6}\end{array}}

\large\boxed{\begin{array}{l}\tt e)~\sf cos(60^\circ)=\dfrac{x}{45}\\\sf\dfrac{1}{2}=\dfrac{x}{45}\\\sf2x=45\\\sf x=\dfrac{45}{2}\\\sf tg(60^\circ)=\dfrac{y}{x}\\\sf\sqrt{3}=\dfrac{y}{\frac{45}{2}}\\\sf y=\dfrac{45\sqrt{3}}{2}\end{array}}

\large\boxed{\begin{array}{l}\tt f)~\sf y^2=x^2+32^2\\\sf y^2=x^2+1024\\\sf obs:faltam~dados~para~calcular~x~e~y.\end{array}}

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