Question

9)Fatore o trinômio quadrado perfeito abaixo: *

100x² + 60x + 9

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Answer 1

Resposta:

Olá! o trinômio do quadrado perfeito é dado pelo:"quadrado do primeiro termo + 2×o primeiro×o segundo+ o quadrado do segundo termo". Para achar a forma fatorada basta achar a raiz quadrada de 100x² e a raiz de 9.

Espero ter ajudado :)

Answer 2

$\Box \ \ \boxed{\begin{array}{l}\sf 100x^2+60x+9 \end{array}}\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf a=100 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf b=60 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf c=9 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf \Delta=60^2-4.100.9 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=3600-3600 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=0 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x=\dfrac{-60\pm\sqrt{\Delta} }{2.a} \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\dfrac{-60\pm0}{200} \end{array}}\\\\\\x'=\dfrac{-60+0}{200} \ \ \ \ \ \ \ x'=\dfrac{-60}{200} \ \ \ \ \ \ \ \ x'=\dfrac{-6}{20} \\\\\\\\x''=\dfrac{-60-0}{200} \ \ \ \ \ \ \ x''=\dfrac{-60}{200} \ \ \ \ \ \ \ \ x''=\dfrac{-6}{20}$

Resposta correta;

$S=\{\dfrac{-6}{20} \}$

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