• Matéria: Matemática
  • Autor: gabrielhilton012
  • Perguntado 4 anos atrás

Dadas as funções f(x) = –3x + 1 e g(x) = 10x – 4, determine:
A) f(0)
-2
1
0
-1
B) f(-2)
-5
7
-3
6
C) g(8)
84
14
76
80
D)g(1/5)
-2
2
-6
4
E) f(-5) + g(-1)
25
2
16
14

Respostas

respondido por: JoséSalatiel
0
  • Após a substituição dos valores na função, obtemos (a) f(0) = 1 ; (b) f(-2) =7 ; (c) g(8) = 76 ; (d) g(1/5) = -2 e (e) f(-5) + g(-1) = 2 .

Dadas as funções definida por f(x) = -3x + 1 e g(x) = 10x - 4, perceba que ao solicitar f(0), f(-2), g(8), g(1/5) e f(-5) + g(-1), já está mostrando o caminho a ser realizado, substituindo x pelos valores atribuídos.

Item (a)

\large{\text{$\sf{f(x)=-3x+1,\;dado\;x = 0.}$}}\\\\\large{\text{$\sf{f(0)=-3\cdot0+1}$}}\\\\\large{\text{$\sf{f(0)=0+1}$}}\\\\\large{\text{$\sf{f(0)=1}$}}

Item (b)

\large{\text{$\sf{f(x)=-3x+1,\;dado\;x = -2.}$}}\\\\\large{\text{$\sf{f(-2)=-3\cdot(-2)+1}$}}\\\\\large{\text{$\sf{f(-2)=6+1}$}}\\\\\large{\text{$\sf{f(-2)=7}$}}

Item (c)

\large{\text{$\sf{g(x)=10x-4,\;dado\;x=8.}$}}\\\\\large{\text{$\sf{g(8)=10\cdot8-4}$}}\\\\\large{\text{$\sf{g(8)=80-4}$}}\\\\\large{\text{$\sf{g(8)=76}$}}

Item (d)

\large{\text{$\sf{g(x)=10x-4,\;dado\;x=\dfrac{1}{5}.}$}}\\\\\\\large{\text{$\sf{g\left(\dfrac{1}{5}\right)=10\cdot\dfrac{1}{5}-4}$}}\\\\\\\large{\text{$\sf{g\left(\dfrac{1}{5}\right)=\dfrac{10}{5}-4}$}}\\\\\\\large{\text{$\sf{g\left(\dfrac{1}{5}\right)=2-4}$}}\\\\\\\large{\text{$\sf{g\left(\dfrac{1}{5}\right)=-2}$}}

Item (e)

\large{\text{$\sf{f(-5)+g(-1)=}$}}\\\\\\\large{\text{$\sf{f(x)=-3x+1,\;dado\;x=-5.}$}}\\\\\large{\text{$\sf{f(-5)=-3\cdot(-5)+1}$}}\\\\\large{\text{$\sf{f(-5)=15+1}$}}\\\\\large{\text{$\sf{f(-5)=16}$}}\\\\\\\large{\text{$\sf{g(x)=10x-4,\;dado\;x=-1.}$}}\\\\\large{\text{$\sf{g(-1)=10\cdot(-1)-4}$}}\\\\\large{\text{$\sf{g(-1)=-10-4}$}}\\\\\large{\text{$\sf{g(-1)=-14}$}}\\\\\\\large{\text{$\sf{f(-5)+g(-1)=16+(-14)=16-14=2}$}}

  • Saiba mais sobre em:

https://brainly.com.br/tarefa/42567832

https://brainly.com.br/tarefa/42679710

Espero ter ajudado.

Bons estudos! :)

Anexos:
Perguntas similares