Question

Dada a função definida por f(x)=x²-5x+6,determine f(0), f(2) e f(3).o resultado obtido respectivamente é:

Answer 1

f(x) = x² - 5x + 6

f(0) = 0² - 5.0 + 6
f(0) = 0 - 0 + 6
f(0) = 6

f(2) = 2² - 5.2 + 6
f(2) = 4 - 10 + 6
f(2) = -6 + 6
f(2) =0

f(3) = 3² - 5.3 + 6
f(3) = 9 - 15 + 6
f(3) = -6 + 6
f(3) = 0 

Answer 2

f(0)

$f(0) = (0)^2-5(0)+6\\\\ \boxed{f(0) = 6}$

f(2)

$f(2) = (2)^2-5(2)+6\\\\\\ f(2) = 4-10+6\\\\ \boxed{f(2) = 0}$

f(3)

$f(3) = (3)^2-5(3)+6\\\\ f(3) = 9-15+6\\\\ \boxed{f(3) = 0}$

Resultados, 6,0 e 0.