Question

Alguém me ajuda é matemática

Answer 1

Resposta:

$E=\frac{2\sqrt{3}-1 }{6}$

Explicação passo-a-passo:

Sen(60°) = $\frac{\sqrt{3} }{2}$

Cos(30°) =  $\frac{\sqrt{3} }{2}$

Sen(150°) = $\frac{1}{2}$

Tg(120°) = $-\sqrt{3}$                  Tg²(120°) = $(-\sqrt{3} )^{2}$

$E=\frac{Sen(60^{o})+cos(30^{o})-sen(150^{o}) }{tg^{2}(120^{o}) }$

$E=\frac{(\frac{\sqrt{3} }{2} ) +(\frac{\sqrt{3} }{2} )-(\frac{1}{2} )}{(-\sqrt{3})^{2} }$

$E = \frac{\frac{\sqrt{3}+\sqrt{3} -1 }{2} }{(-\sqrt{3})^{2}}$

$E=\frac{\frac{2\sqrt{3}-1 }{2} }{(-\sqrt{3})^{2}}$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{(-\sqrt{3})^{2}}$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{(3^{\frac{1}{2} } )^{2} }$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{3^{\frac{1X2}{2} } }$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{3^{\frac{2}{2} } }$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{3^{1} }$

$E=\frac{2*\frac{\sqrt{3} }{2}-\frac{1}{2} }{3}$

$E=\frac{\frac{2\sqrt{3}-1}{2} }{3}$

$E=\frac{2\sqrt{3}-1 }{2X3}$

$E=\frac{2\sqrt{3}-1 }{6}$