• Matéria: Matemática
  • Autor: Mjchely
  • Perguntado 9 anos atrás

A e B são matrizes quadradas de ordem 2, cujos elementos são dados por aij=3j-2j e bij=(aij) ao quadrado. cálcule: A-B e A+B

Respostas

respondido por: Maghayver
10
a_{11}=3.1-2.1=1 \\ a_{12}=3.2-2.2=2 \\ a_{21}=3.1-2.1=1 \\ a_{22}=3.2-2.2=2 \\  \\  A= \left[\begin{array}{ccc}1&2\\1&2\end{array}\right] \\  \\ B=\left[\begin{array}{ccc}1&2\\1&2\end{array}\right] \\  \\ A+B \\ \\  \left[\begin{array}{ccc}1&2\\1&2\end{array}\right]+\left[\begin{array}{ccc}1&2\\1&2\end{array}\right]=\left[\begin{array}{ccc}1+1&2+2\\1+1&2+2\end{array}\right]=\left[\begin{array}{ccc}2&4\\2&4\end{array}\right]

Agora A - B

\left[\begin{array}{ccc}1&2\\1&2\end{array}\right]-\left[\begin{array}{ccc}1&2\\1&2\end{array}\right]=\left[\begin{array}{ccc}1-1&2-2\\1-1&2-2\end{array}\right]=\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]
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