Question

Calcule o perimetro do quadrilatero de vertices A (1,3) B (-2,2) C (-1,-2) e D (2,-2)

Answer 1

Ola Nlz

AB² = 3² + 1² = 9 + 1 = 10 √ Δ² 
AB = √10

BC² = 1² + 4² = 1 + 16 = 17
BC = √17 

CD² = 3² + 0² = 9
CD = 3

AD² = 1² + 5² = 1 + 25 = 26 
AD = √26 

perímetro

P = 3 + √10 + √17 + √26 = 15.38 

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