Question

4)resolva:

a)2⁴÷4+3².10=
b)(12²+1)÷(54-7²)-3³=
c)7²-40+18÷3²-10=
d)(6²-5²).3³-10²=
e)6²÷(2³+1).(3²-5)=
f)(7.3).10³=
g)(7.3²-1)÷(8²-2.31)=
h)2+4²-2³.3=
i)(2+4²-2³).3=
j)2+(4²-2).3=

me ajudemm​

Answer 1

Resposta:

a)2⁴÷4+3².10=

16 : 4 + 9 . 10 =

4 + 9 . 10 =

4 + 90 = 94

b) (12²+1)÷(54-7²)-3³=

(144 + 1 ) : ( 54 - 49) - 27 =

145 : 5 - 27 =

29 - 27 = 2

c) 7²-40+18÷3²-10 =

49 - 40 + 18 : 9 - 10 =

49 - 40 + 2 - 10 =

9 - 8 = 1

d) (6²-5²).3³-10²=

(36 - 25) . 27 - 100 =

11 . 27 - 100 =

297 - 100 = 197

e)6²÷(2³+1).(3²-5)=

36 : ( 8 + 1 ) . ( 9 - 5 ) =

36 : 9 . 4 =

4 . 4 = 16

f)(7.3).10³=

21 . 1000 = 21.000

g)(7.3²-1)÷(8²-2.31)=

( 7 . 9 - 1 ) : ( 64 -2 . 31) =

( 63 - 1 ) : ( 64 - 62) =

62 : 2 = 31

h)2+4²-2³.3=

2 + 16 - 8 . 3 =

2 + 16 - 24 =

18 - 24 = -6

i)(2+4²-2³).3=

( 2 + 16 - 8 ) . 3 =

(18 - 8 ) . 3 =

10 . 3 = 30

j)2+(4²-2).3=

2+ ( 16 - 2) . 3 =

2 + 14 . 3 =

2 + 42= 44

Explicação passo-a-passo:

Espero ter ajudado (/ >.<)/ <3 . * :