Question

Como que eu resolvo
a) -5 + (-8-2)
b)(-5+10) X (-2-10)
c)Chaves-10-colchetes+12-(+18-25)-10colchete+18chaves
Respondam com conta pf

Answer 1

$a) -5+(-8-2)=-5-10=-15 \\ \\ \\ b)(-5+10).(-2-10)=5.(-12)=-60 \\ \\ \\ c){-10-[+12-(+18-25)-10]+18}= \\ \\ ={-10-[+12-(-7)-10]+18}= \\ \\ ={-10-[12+7-10]+18}= \\ \\ =-10-9+18=-1$

Answer 2

a) -5 + (-8-2) = - 5 + (-6) = - 5 - 6 ==> - 11
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b)(-5+10) X (-2-10) = (+5) x ( - 12) = - 60
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c)Chaves-10-colchetes+12-(+18-25)-10colchete+18chaves

{ - 10 - [+12 - ( +18-25) - 10] + 18}

{ - 10 - [+12 - ( - 7 - 10] + 18}

{ - 10 - [+12 - ( - 17] + 18}

{ - 10 - [+12 + 17 + 18}

{ - 10 - [+ 47}

{ - 10 - 47 }

- 57