Question

2 • log x = log 2x - log 3

Answer 1

$\large\boxed{\begin{array}{l}\sf 2\ell ogx=\ell og2x-\ell o g3\\\sf \ell og2x-2\ell ogx=3\\\sf \ell og2x-\ell og x^2=\ell og3\\\sf \ell og\bigg(\dfrac{2\backslash\!\!\!x}{\backslash\!\!\!x^2}\bigg)=\ell og3\\\sf \ell og\bigg(\dfrac{2}{x}\bigg)=\ell og3\\\sf \dfrac{2}{x}=3\\\sf 3x=2\\\sf x=\dfrac{2}{3}\end{array}}$