Question

No plano cartesiano, o triangulo de vértices
A(1, 2), B(m, 4) e C(0, 6) e retângulo em A. Qual o valor de m?

Answer 1

A(1, 2), B(m, 4) e C(0, 6)

dAB²=(1-m)² +(2-4)²

dAC²=(1-0)²+(2-6)²

dBC²=(m-0)²+(4-6)²

dBC²= dAB² +dAC²

(m-0)²+(4-6)²  = (1-m)² +(2-4)²  + (1-0)²+(2-6)²

m² +4 =1-2m+m² + 4  +1  +16

0 =1-2m  +1  +16

2m = 18

m=18/2

m= 9