• Matéria: Matemática
  • Autor: marcoaurelioalunoplu
  • Perguntado 4 anos atrás

responda esse calcule essas potencias

Anexos:

Respostas

respondido por: Anônimo
3

꧁Hello, how are you?꧂

  • Bom... vamos , baby!

a) \:  \: {\purple{( \sqrt{15}) {}^{2}  }} \\  \\ {\purple{ \sqrt{15} {}^{2}  }} \\  \\ {\purple{15}}

b) \:  \: {\purple{(3 \sqrt{7}) {}^{2}  }} \\  \\ {\purple{3 {}^{2} \times  \sqrt{7} {}^{2}   }} \\  \\ {\purple{9 \times  \sqrt{7 {}^{} } {}^{2}  }} \\  \\ {\purple{9 \times 7}} \\  \\ {\purple{63}}

c) \:  \: {\purple{( \sqrt{7} +  \sqrt{3} ) {}^{2}  }} \\  \\ {\purple{ \sqrt{7 } {}^{2}  + 2 \sqrt{7} \sqrt{3} +  \sqrt{3} {}^{2}     }} \\  \\ {\purple{7 + 2 \sqrt{7} \sqrt{3}  +  \sqrt{3} {}^{2}   }} \\  \\ {\purple{7 + 2 \sqrt{21} +  \sqrt{3} {}^{2}   }} \\  \\ {\purple{7 + 2 \sqrt{21} + 3 }} \\  \\ {\purple{10 + 2 \sqrt{21} }} \\  \\ {\purple{}}

d) \:  \:{\purple{(3 -  \sqrt{7}) {}^{2}  }} \\  \\ {\purple{3 {}^{2} - 2 \times 3 \sqrt{7}  +  \sqrt{7} {}^{2}   }} \\  \\ {\purple{9 - 2 \times 3 \sqrt{7} +  \sqrt{7}  {}^{2}  }} \\  \\ {\purple{9 - 6 \sqrt{7}  +  \sqrt{7} {}^{2}  }} \\  \\ {\purple{9 - 6 \sqrt{7} + 7 }} \\  \\ {\purple{16 - 6 \sqrt{7} }} \\  \\ {\purple{}}

{\purple{Keep \:  loving...}}

━━━━━ • ஜ • ❈ • ஜ • ━━━━━

Signed: Lohany Queen of hell 彡★

━━━━━ • ஜ • ❈ • ஜ • ━━━━━

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