a)raiz de 24 + raiz de 96
b)raiz de 44 - raiz de 99
c)³raiz de 500 - ³raiz de 4
ME AJUDEM POR FAVOR E PRA HOJE A TARDE E NÃO SEI RESPONDER...
Respostas
respondido por:
13
Bom dia Juliano!
Solução!
Antes de resolver as raizes,tem que decompor os radicando em fatores primos.
![A)~~ \sqrt{44}- \sqrt{99}\\\\\
\sqrt{2^{2}.11}- \sqrt{3^{2}.11 }\\\\\\
2 \sqrt{11}- 3\sqrt{11}\\\\\\
(2-3) \sqrt{11}\\\\\\
- \sqrt{11}](https://tex.z-dn.net/?f=A%29%7E%7E+%5Csqrt%7B44%7D-+%5Csqrt%7B99%7D%5C%5C%5C%5C%5C%0A+%5Csqrt%7B2%5E%7B2%7D.11%7D-+%5Csqrt%7B3%5E%7B2%7D.11+%7D%5C%5C%5C%5C%5C%5C%0A2+%5Csqrt%7B11%7D-+3%5Csqrt%7B11%7D%5C%5C%5C%5C%5C%5C%0A%282-3%29+%5Csqrt%7B11%7D%5C%5C%5C%5C%5C%5C%0A-+%5Csqrt%7B11%7D++++++++ "A)~~ \sqrt{44}- \sqrt{99}\\\\\
\sqrt{2^{2}.11}- \sqrt{3^{2}.11 }\\\\\\
2 \sqrt{11}- 3\sqrt{11}\\\\\\
(2-3) \sqrt{11}\\\\\\
- \sqrt{11}")
![B)~~ \sqrt[3]{500}- \sqrt[3]{4} \\\\\\
\sqrt[3]{5^{3}.4 }- \sqrt[3]{4} \\\\\\
5 \sqrt[3]{4}- \sqrt[3]{4}\\\\\
(5-1)\sqrt[3]{4}\\\\
4\sqrt[3]{4}](https://tex.z-dn.net/?f=B%29%7E%7E+%5Csqrt%5B3%5D%7B500%7D-+%5Csqrt%5B3%5D%7B4%7D+%5C%5C%5C%5C%5C%5C%0A+%5Csqrt%5B3%5D%7B5%5E%7B3%7D.4+%7D-++%5Csqrt%5B3%5D%7B4%7D+%5C%5C%5C%5C%5C%5C%0A5+%5Csqrt%5B3%5D%7B4%7D-+%5Csqrt%5B3%5D%7B4%7D%5C%5C%5C%5C%5C%0A%285-1%29%5Csqrt%5B3%5D%7B4%7D%5C%5C%5C%5C%0A4%5Csqrt%5B3%5D%7B4%7D+ "B)~~ \sqrt[3]{500}- \sqrt[3]{4} \\\\\\
\sqrt[3]{5^{3}.4 }- \sqrt[3]{4} \\\\\\
5 \sqrt[3]{4}- \sqrt[3]{4}\\\\\
(5-1)\sqrt[3]{4}\\\\
4\sqrt[3]{4}")
Bom dia!
Bons estudos!
Solução!
Antes de resolver as raizes,tem que decompor os radicando em fatores primos.
Bom dia!
Bons estudos!
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